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80 lines
2.7 KiB
80 lines
2.7 KiB
/**
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* @Author: River_qiu
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* @Date: 2021/11/18
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*/
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// 表格单元格合并多列
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let [spanObj, pos] = [{}, {}]
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//spanObj 存储每个key 对应的合并值
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//pos 存储的是 key合并值得索引 大概吧
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export const dataMethod = (data, isH, allColumns = []) => {
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//循环数据(行)
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for (let i in data) {
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let dataI = data[i]
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//循环数据内对象，查看有多少key
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if (allColumns.length > 0) {
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let preProp = undefined
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// dataI.historyValue =
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// 循环列数据
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for (let index = 0; index < allColumns.length; index++) {
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let j = allColumns[index]
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if (i == 0) {
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// 第一行，每列至少展示1行
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spanObj[j] = [1]
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pos[j] = 0
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} else {
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if (index == 0) {
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data[i].historyValue = ''
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data[i - 1].historyValue = ''
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} else {
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data[i].historyValue += data[i][preProp]
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data[i - 1].historyValue += data[i - 1][preProp]
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}
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// e: 当前行数据，k：上一行数据
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let [e, k] = [dataI, data[i - 1]]
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// 判断上一行数据是否存在
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// 空数据不合并
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// 前一列值相同并且不为空或者为第一列
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// 存在当前的列的值与上一行是否一样
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// 判断是否有数组规定只允许那几列需要合并单元格的
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if (
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k &&
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e[j] &&
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(!preProp || (e.historyValue && e.historyValue == k.historyValue)) &&
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e[j] == k[j] &&
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(!isH || isH.length == 0 || isH.includes(j))
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) {
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//如果上一级和当前一级相当，数组就加1 数组后面就添加一个0
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spanObj[j][pos[j]] += 1
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spanObj[j].push(0)
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} else {
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spanObj[j].push(1)
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pos[j] = i
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}
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preProp = j
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}
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}
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} else {
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for (let j in dataI) {
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//如果只有一条数据时默认为1即可，无需合并
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if (i == 0) {
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spanObj[j] = [1]
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pos[j] = 0
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} else {
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let [e, k] = [dataI, data[i - 1]]
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//判断上一级别是否存在 ，
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//存在当前的key是否和上级别的key是否一样
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//判断是否有数组规定只允许那几列需要合并单元格的
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if (k && e[j] && k[j] && e[j] == k[j] && (!isH || isH.length == 0 || isH.includes(j))) {
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//如果上一级和当前一级相当，数组就加1 数组后面就添加一个0
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spanObj[j][pos[j]] += 1
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spanObj[j].push(0)
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} else {
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spanObj[j].push(1)
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pos[j] = i
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}
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}
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}
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}
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}
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return spanObj
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}
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